设4阶矩阵a满足|2e+a|=0
24直播网 / 设4阶矩阵a满足|2e+a|=0- 设4阶矩阵a满足|2e+a|=02025-02-14
- a为4阶矩阵,且满足|a|=22025-02-14
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- 设4阶矩阵a满足a3=a2025-02-14
- 设有四阶方阵a满足|3e+a|=02025-02-14
- 设四阶矩阵b满足2025-02-14
- 设四阶矩阵b满足(1/4a*)^-1ba^-1=2ab+e2025-02-14
- 设4阶矩阵a=(α,γ2,γ3,γ4)2025-02-14
- 设4阶矩阵a=()2025-02-14
- 设n阶矩阵a满足a^2+4a+4e=0 求出a的所有特征值2025-02-14
- 设4阶矩阵a满足|2e+a|=02025-02-14
- a为4阶矩阵,且满足|a|=22025-02-14
- 设a是4阶矩阵且满足a^2=a,求r(a-2e)2025-02-14
- 设4阶矩阵a满足a3=a2025-02-14
- 设有四阶方阵a满足|3e+a|=02025-02-14
- 设四阶矩阵b满足2025-02-14
- 设四阶矩阵b满足(1/4a*)^-1ba^-1=2ab+e2025-02-14
- 设4阶矩阵a=(α,γ2,γ3,γ4)2025-02-14
- 设4阶矩阵a=()2025-02-14
- 设n阶矩阵a满足a^2+4a+4e=0 求出a的所有特征值2025-02-14